Answered

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A bottle contains 750mL of fruit punch with a concentration of 50% pure fruit juice. Johan
drinks 100mL of the punch and then refills the bottle with an equal amount of a cheaper
brand of punch. If the concentration of juice in the bottle is now reduce to 48%, what was
the concentration in the punch that Johan added?​

Sagot :

francocanacari

Answer:

The juice concentration in the punch that Johan added was 35%.

Step-by-step explanation:

Since a bottle contains 750mL of fruit punch with a concentration of 50% pure fruit juice, and Johan drinks 100mL of the punch and then refills the bottle with an equal amount of a cheaper brand of punch, if the concentration of juice in the bottle is now reduced to 48%, to determine what was the concentration in the punch that Johan added, the following calculation must be performed:

750 = 100

650 = X

650 x 100/750 = X

65000/750 = X

86,666 = X

86.666 x 0.5 + 13.333 x 0.4 = 0.486662

86.666 x 0.5 + 13.333 x 0.39 = 0.4853287

86.666 x 0.5 + 13.333 x 0.35 = 0.4799955

Thus, the juice concentration in the punch that Johan added was 35%.

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