Answer:
2x - 7y = -34.
Step-by-step explanation:
As the line we want is perpendicular to y= -7/2 x + 9 it's slope will be
-1 /(-7/2) = 2/7.
Now we find the point of intersection ofn the 2 given lines:
x + y = 10
3x - 4y = -12
Multiply the first equation by -3:
-3x - 3y = -30
Now add this last equation to the second one:
-7y = -42
y = 6
Plug y = 6 into the first equation:
x + 6 = 10
x = 4.
So the point of intersection is (4, 6) and the equation we want passes through this, so using the point-slope form of straight line we have:
y - 6 = 2/7(x - 4)
7y - 42 = 2(x - 4)
7y - 42 = 2x - 8
2x - 7y = -42 + 8
2x - 7y = -34
Answer:
y=(2/7)x+(7/3)
Step-by-step explanation:
y=-7/2(x)+9
y=mx+c
Therefore, slope of line y is -7/2
Because line y perpendicular to the required line
Therefore, slope of the required line is 2/7
x+y=10 ........(1)
3x-4y = -12 ......(2)
(1) x 4:
4x+4y =40 ......(3)
(3) + (2)
4x+4y+3x-4y=28
x=4
by substituting x=4 into (1), we have
y=10-4=6
Therefore, the point that the line intersects is (4, 6)
let y=(2/7)x+c be the required equation
(4, 6):
6=(2/7)4+c
c=21/4
therefore, the required equation is y=(2/7)x+(7/3).