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Sagot :
Answer:
see explanation
Step-by-step explanation:
(a)
Given
[tex]\frac{y}{3}[/tex] + [tex]\frac{y+3}{5}[/tex]
The common denominator is 15 ( the LCM of 3 and 5 )
Multiply numerator/ denominator of first fraction by 5
Multiply the numerator/ denominator of second fraction by 3
= [tex]\frac{5y}{15}[/tex] + [tex]\frac{3y+9}{15}[/tex] ← add numerators , leaving denominator of 15
= [tex]\frac{5y+3y+9}{15}[/tex]
= [tex]\frac{8y+9}{15}[/tex]
(b)
Given
[tex]\frac{3x}{8}[/tex] - [tex]\frac{x+5}{4}[/tex]
The common denominator is 8 ( the LCM of 8 and 4 )
Multiply numerator/ denominator of second fraction by 2
= [tex]\frac{3x}{8}[/tex] - [tex]\frac{2(x+5)}{8}[/tex] ← simplify numerators leaving denominator of 8
= [tex]\frac{3x-2x-10}{8}[/tex]
= [tex]\frac{x-10}{8}[/tex]
Answer:
a) (8y + 9)/15.
b) (5x + 10)/8.
Step-by-step explanation:
(a) y/3 + (y + 3)/5
The LCD of 3 and 5 is 15 so we have:
5y/15 + 3(y + 3)/15
= (5y + 3(y + 3)) / 15
= (5y + 3y + 9)/15
= (8y + 9)/15.
b) 3x/8 + (x + 5)/4
The LCD of 4 and 8 is 8 so we have:
3x/8 + 2(x + 5)/8
= (3x + 2x + 10) / 8
= (5x + 10)/8.
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