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How does the rate of a chemical reaction change if the concentration of both reactants increases 4 times?

2NO + O2 → 2 NO2

Sagot :

Answer: The rate will increase 32 times if the concentration of both reactants increases 4 times

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

For the reaction : [tex]2NO+O_2\rightarrow 2NO_2[/tex]  [tex]rate=k[NO]^2[O_2]^1[/tex]  

k= rate constant

order with respect to [tex]NO_2[/tex] = 2

order with respect to [tex]O_2[/tex] = 1

Thus on increasing the concentration of reactants 4 times :

[tex]rate'=k[4\times NO]^2[4\times O_2]^1[/tex]

[tex]rate'=k\times 8\times 4\times [NO]^2\times [O_2]^1[/tex]

[tex]rate'=32\times rate[/tex]

Thus rate will increase 32 times if the concentration of both reactants increases 4 times

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