Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Join our platform to connect with experts ready to provide detailed answers to your questions in various areas. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

A hang glider dropped his cell phone from a height of 450 feet. How many seconds did it take for the cell phone to reach the ground?

Sagot :

Answer:

t = 9.58 s

Step-by-step explanation:

Given that,

The height from where the cell phone is dropped, h = 450 feet

We need to find the time for the cell phone to reach the ground. Let the time be t. Using second equation of kinematics to find it.

[tex]h=ut+\dfrac{1}{2}at^2[/tex]

u is initial velocity, u = 0

a = g

So,

[tex]h=\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\times 450}{9.8}} \\\\t=9.58\ s[/tex]

So, it will take 9.58 seconds to reach the ground.