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A hang glider dropped his cell phone from a height of 450 feet. How many seconds did it take for the cell phone to reach the ground?

Sagot :

Answer:

t = 9.58 s

Step-by-step explanation:

Given that,

The height from where the cell phone is dropped, h = 450 feet

We need to find the time for the cell phone to reach the ground. Let the time be t. Using second equation of kinematics to find it.

[tex]h=ut+\dfrac{1}{2}at^2[/tex]

u is initial velocity, u = 0

a = g

So,

[tex]h=\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\times 450}{9.8}} \\\\t=9.58\ s[/tex]

So, it will take 9.58 seconds to reach the ground.