Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

PLEASE HELP I'M SO DOOMED
A balloon that contains 2.8 mol of helium gas has a volume of 31 L. If 3.5 g of helium is added, what will be the new volume of the balloon? Assume the temperature and pressure remain the same. The molar mass of helium is 4.00 g/mol.
a) 186 L
b) 70 L
c) 24 L
d) 41 L
Do not post links

Sagot :

Akzoo

Answer:

D

Explanation:

31 / 2.8 = 11.0714286 L per mole of helium

3.5 / 4 = 0.875 moles

2.8 + 0.875 = 3.675 moles

11.0714286 x 3.675 = 40.6875 L

Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.