Answered

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john is placing cement tiles for a patio in a rectangle surrounding a rectangular fire pit. The fire pit has a width of x ft and a length that is 5 times the width. The entire patio is 6ft wider and 19 ft longer than the fire pit. What is the area that he will need to buy tiles for?

Sagot :

Answer:

49x + 114

Step-by-step explanation:

[   [ fireplace ] x   = area of 5[tex]x^{2}[/tex]                   ]  x + 6

     5x

   patio               = area of 5[tex]x^{2}[/tex] + 49x + 114

5x + 19

 

(5x + 19) ( x + 6) = 5[tex]x^{2}[/tex] + 19x + 30x + 114

(5[tex]x^{2}[/tex] + 49x + 114)                     -   (5[tex]x^{2}[/tex] )                         =           49x + 114

(area of patio and fireplace) - (area of fireplace)     =       (area of patio only)

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