Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

A 5.0 g sample of a pesticide was decomposed with metallic sodium in alcohol, and the liberated chloride ion was precipitated with AgCl. Express the results of this analysis in terms of percent DDT (C14H9Cl5, molar mass, 354.72 g/mol)) based on the recovery of 0.1606 g of AgCl

Sagot :

maacastrobr

Answer:

1.59%

Explanation:

First, we convert 0.1606 g of AgCl into moles, using its molar mass:

  • 0.1606 g ÷ 143.32 g/mol = 1.12x10⁻³ mol AgCl

Then we convert the calculated moles of Cl (equal to AgCl moles) into moles of DDT:

  • 1.12x10⁻³ mol Cl * [tex]\frac{1molDDT}{5molCl}[/tex] = 2.24x10⁻⁴ mol DDT

Now we convert 2.24x10⁻⁴ moles of DDT into grams, using its molar mass:

  • 2.24x10⁻⁴ mol DDT * 354.48 g/mol = 0.0794 g

Finally we calculate the percentage of DDT in the sample:

  • 0.0794 g / 5.0 * 100% = 1.59%

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.