Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

A 5.0 g sample of a pesticide was decomposed with metallic sodium in alcohol, and the liberated chloride ion was precipitated with AgCl. Express the results of this analysis in terms of percent DDT (C14H9Cl5, molar mass, 354.72 g/mol)) based on the recovery of 0.1606 g of AgCl

Sagot :

maacastrobr

Answer:

1.59%

Explanation:

First, we convert 0.1606 g of AgCl into moles, using its molar mass:

  • 0.1606 g ÷ 143.32 g/mol = 1.12x10⁻³ mol AgCl

Then we convert the calculated moles of Cl (equal to AgCl moles) into moles of DDT:

  • 1.12x10⁻³ mol Cl * [tex]\frac{1molDDT}{5molCl}[/tex] = 2.24x10⁻⁴ mol DDT

Now we convert 2.24x10⁻⁴ moles of DDT into grams, using its molar mass:

  • 2.24x10⁻⁴ mol DDT * 354.48 g/mol = 0.0794 g

Finally we calculate the percentage of DDT in the sample:

  • 0.0794 g / 5.0 * 100% = 1.59%

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.