Answer:
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answer :
number of moles
Acetic acid = 0.061199 mole
Alcohol = 0.027320 mole
Explanation:
The starting volumes : 2.5mL of either alcohol and 3.5mL of either acid
for the purpose of this solution I will take 2.5 mL of 1-butanol and 3.5 mL of acetic acid
mass of 1-Butanol = 2.5 mL * 0.81 g/mol = 2.025 g
∴ number of moles of 1-butanol = 2.025g / 74.12 g/mol = 0.027320 mole
mass of acetic acid = 3.5 mL * 1.05 g/mol = 3.675 g
∴ number of moles of Acetic acid = 3.675 g/ 60.05 g/mol = 0.061199 mole
Reaction equation
CH3-CH2-CH2-CH2-OH + CH3-COOH + H+ (cat) ↔ CH3-CH2-CH2-CH2-O-CO-CH3 + H2O
