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2) A 0.4 kg ball moves in horizontal circle of radius 3 mat speed of 100m/s. What
is the centripetal force?
file the​


Sagot :

9514 1404 393

Answer:

  1333.3 N

Step-by-step explanation:

The centripetal acceleration is given by ...

  a = v^2/r

  a = (100m/s)^2/(3 m) = (10^4)/3 m/s^2

Then the force on the ball is ...

  F = Ma = (0.4 kg)(10^4)/3 kg·m/s^2 ≈ 1333.3 N