Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

When a magnetic field is first turned on, the flux through a 20-turn loop varies with time according to Φm=5.0t2−2.0t, where Φm is in milliwebers, t is in seconds, and the loop is in the plane of the page with the unit normal pointing outward. (a) What is the emf induced in the loop as a function of time? What is the direction of the induced current at (b) t = 0, (c) 0.10, (d) 1.0, and (e) 2.0 s?

Sagot :

batolisis

Answer:

A) ( - 200t + 40 ) volts

B)  b) anticlockwise ,  c) anticlockwise , d) clockwise ,  e) clockwise

Explanation:

Given data:

magnetic flux (Φm) = 5.0t^2 − 2.0t

number of turns = 20

a) determine induced emf

E = - N [tex]\frac{d\beta }{dt}[/tex]

  =  - N ( 10t - 2 ) = - 20 ( 10t - 2 )

  =  - 200t + 40  volts

b) Determine direction of induced current

i) at t = 0

 E = - 0 + 40  ( anticlockwise direction )

ii) at t = 0.10

E = -20 + 40 =  20 ( anticlockwise direction )

iii) at t = 1

E = - 200 + 40 = - 160 ( clockwise direction)

iv) at t = 2

E = -400 + 40 =  - 360 ( clockwise direction )

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.