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Sagot :
Answer:
0.6946 = 69.46% probability that a randomly selected Republican voter from the exit poll is from a household that makes at least $50,000.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Republican
Event B: From a household that makes at least $50,000.
Probability of Republican:
43% of 36%(makes less than $50,000).
55% of 64%(makes more than $50,000).
So
[tex]P(A) = 0.43*0.36 + 0.55*0.64 = 0.5068[/tex]
Republican and from a household that makes at least $50,000.
55% of 64%. So
[tex]P(A \cap B) = 0.55*0.64 = 0.352[/tex]
What is the probability that a randomly selected Republican voter from the exit poll is from a household that makes at least $50,000?
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.352}{0.5068} = 0.6946[/tex]
0.6946 = 69.46% probability that a randomly selected Republican voter from the exit poll is from a household that makes at least $50,000.
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