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If f(x) is an exponential function where f(- 2.5) = 9 and f(2.5) = 45 , then find the value of f(3.5) , to the nearest hundredth

Sagot :

abidemiokin

The value of g(3.5) is 41.49 to the nearest hundredth

Exponential function

The standard exponential function is given as g(x) = ab^x

If g(-2.5) = 9 and g(2.5) = 45, hence;

9 = ab^-2.5 .............. 1

45 = ab^2.5 .............2

Divide both equations:

9/45 = b^{-2.5-2.5}

1.5 = b^-5

1.5= 1/b^5

b^5 = 0.6666

b = 0.922

Also since 45 = ab^2.5 .

45 = a(0.922)^2.5

45 = 0.81625a

a = 55.13

g(3.5) = 55.13(0.922)^3.5

g(3.5) = 41.49

Hence the value of g(3.5) is 41.49 to the nearest hundredth

Learn more on exponential function here: https://brainly.com/question/12940982

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