Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

At am outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of 29.8981 cm on spring with a spring constant

Sagot :

Answer:

Hello your question lacks some very vital information hence I will give you a general equation where you can input the missing values and get your answer

answer :  mass of Bananas ( m ) = [tex]\frac{A^2}{V^2} * K[/tex]

To calculate for weight of Bananas  = m * g      where g = 9.8

Explanation:

Given an amplitude ( A )= 29.8981

Spring constant = x ( unknown )

maximum speed of Bananas( v ) = wA  ( unknown )

question : calculate the weight of the bananas

First  step : calculate the period of oscillation

T = [tex]\frac{2\pi }{vA}[/tex] --- ( 1 )

next step : express T in terms of mass ( m ) of the bananas

= [tex]2\pi \sqrt{\frac{m}{k} } = \frac{2\pi }{vA}[/tex]

∴ m/k = A^2 / v^2

hence  mass of Bananas ( m ) = [tex]\frac{A^2}{V^2} * K[/tex]

To calculate for weight = m * g