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At am outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of 29.8981 cm on spring with a spring constant

Sagot :

batolisis

Answer:

Hello your question lacks some very vital information hence I will give you a general equation where you can input the missing values and get your answer

answer :  mass of Bananas ( m ) = [tex]\frac{A^2}{V^2} * K[/tex]

To calculate for weight of Bananas  = m * g      where g = 9.8

Explanation:

Given an amplitude ( A )= 29.8981

Spring constant = x ( unknown )

maximum speed of Bananas( v ) = wA  ( unknown )

question : calculate the weight of the bananas

First  step : calculate the period of oscillation

T = [tex]\frac{2\pi }{vA}[/tex] --- ( 1 )

next step : express T in terms of mass ( m ) of the bananas

= [tex]2\pi \sqrt{\frac{m}{k} } = \frac{2\pi }{vA}[/tex]

∴ m/k = A^2 / v^2

hence  mass of Bananas ( m ) = [tex]\frac{A^2}{V^2} * K[/tex]

To calculate for weight = m * g

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