At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

A population of capybaras contains 104 individuals. Studying them you discover that they have two types of alleles for a certain gene. The frequency of the recessive allele (c) is 0.3 and we assume that this is an ideal population with simple dominance. a. Calculate the frequency of the dominant allele, C. b. Calculate the genotype frequencies in the next generation (F1) c. Calculate the phenotype frequencies of F1 d. Calculate the heterozygosity (H) e. Calculate the number of heterozygous individuals in the wild population

Sagot :

Answer:

a.

  • f(C) = p = 0.7

b.  

  • F(CC) = p² = 0.49
  • F(cc) = q² = 0.09
  • F(Cc) = 2pq = 0.42

c.

  • F(C-) = 0.91
  • F(cc) = 0.09

d.

  • F(Cc) = 2pq = 0.42

e.

  • 43.68 individuals Cc

Explanation:

Due to technical problems, you will find the complete explanation in the attached files