Answered

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A parabola has a vertex (-3, -2) and contains the point (-5, 6). Write the equation for this parabola in vertex form.

Sagot :

MrRoyal

Answer:

[tex]y = 2(x +3)^2 -2[/tex]

Step-by-step explanation:

Given

[tex](h,k) = (-3,-2)[/tex] --- vertex

[tex](x,y) = (-5,6)[/tex] --- point

Required

Determine the equation

The general form is:

[tex]y = a(x - h)^2 + k[/tex]

First, we solve for a:

Substitute [tex](h,k) = (-3,-2)[/tex] and [tex](x,y) = (-5,6)[/tex] in [tex]y = a(x - h)^2 + k[/tex]

[tex]6 = a(-5 - (-3))^2 - 2[/tex]

[tex]6 = a(-2)^2 - 2[/tex]

[tex]6 = 4a - 2[/tex]

Solve for a

[tex]4a = 6 + 2[/tex]

[tex]4a = 8[/tex]

[tex]a = 2[/tex]

So:

[tex]y = a(x - h)^2 + k[/tex]

[tex]y = 2(x - (-3))^2 -2[/tex]

[tex]y = 2(x +3)^2 -2[/tex]

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