Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
if the value of the volume of the cone let says the radius is 1 and the height is 2. Then the volume is 2pi. If the height is now 4, then it just doubled.
Answer-
When the height is doubled, the volume of the cone also gets doubled.
Solution-
Volume of a cone is given by,
[tex]V=\dfrac{\pi \times r^2\times h}{3}[/tex]
Where,
V = Volume,
r = radius of the base,
h = height of the cone.
Let, height at first be x, then volume would be,
[tex]V_1=\dfrac{\pi \times r^2\times x}{3}[/tex]
As the height is doubled, so height = 2x, then volume would be,
[tex]V_2=\dfrac{\pi \times r^2\times 2x}{3}\\\\=2\times \dfrac{\pi \times r^2\times x}{3}\\\\=2\times V_1[/tex]
Therefore, when the height is doubled, the volume of the cone also gets doubled.
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.