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What happens to the volume of a cone when the height is doubled ?


Sagot :

if the value of the volume of the cone let says the radius is 1 and the height is 2. Then the volume is 2pi. If the height is now 4, then it just doubled.

Answer-

When the height is doubled, the volume of the cone also gets doubled.

Solution-

Volume of a cone is given by,

[tex]V=\dfrac{\pi \times r^2\times h}{3}[/tex]

Where,

V = Volume,

r = radius of the base,

h = height of the cone.

Let, height at first be x, then volume would be,

[tex]V_1=\dfrac{\pi \times r^2\times x}{3}[/tex]

As the height is doubled, so height = 2x, then volume would be,

[tex]V_2=\dfrac{\pi \times r^2\times 2x}{3}\\\\=2\times \dfrac{\pi \times r^2\times x}{3}\\\\=2\times V_1[/tex]

Therefore, when the height is doubled, the volume of the cone also gets doubled.