Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

## Sagot :

**Answer-**

*When the height is doubled, the volume of the cone also gets*** doubled.**

**Solution-**

Volume of a cone is given by,

[tex]V=\dfrac{\pi \times r^2\times h}{3}[/tex]

Where,

V = Volume,

r = radius of the base,

h = height of the cone.

Let, height at first be x, then volume would be,

[tex]V_1=\dfrac{\pi \times r^2\times x}{3}[/tex]

As the height is doubled, so height = 2x, then volume would be,

[tex]V_2=\dfrac{\pi \times r^2\times 2x}{3}\\\\=2\times \dfrac{\pi \times r^2\times x}{3}\\\\=2\times V_1[/tex]

Therefore, when the height is doubled, the volume of the cone also gets doubled.