Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

SOLVING SYSTEMS OF EQUATIONS BY SUBSTITUTION.
x+3y=12
x-y=8

Sagot :

luana
[tex] \left \{ {{x+3y=12} \atop {x-y=8}} \right. \\\\ \left \{ {{x=12-3y} \atop {x=8+y}} \right. \\\\ 12-3y=8+y\ \ \ | subtract\ y\\\\ -4y+12=8\ \ \ | subtract\ 12\\\\ -4y=-4\ \ \ | divide\ by\ -4\\\\ y=1\\\\ x=8+y=8+1=9[/tex]
First, we need to find any value for x or y (I will do x)
So, taking x-y=8, if you add y, you get x=8+y. Even though this is not a real integer, we can still substitute it into the other equation. So, because x = 8+y, then, 8+y + 3y = 12. Then solve it by adding like terms, 8+4y=12, then subtract 8, 4y=4, and last, divide by four. y=1. However, we are not done yet, by substituting the value of y into the second equation, we get x-1=8. Add one and x=9.
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.