Answered

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This is the equation for the combustion of propane.

C3H8 + 5O2 → 3CO2 + 4H2O + heat

Which are the reactants and the products in this reaction?

A.
The reactants are C3H8 (propane) and H2O (water). The products are O2 (oxygen) and CO2 (carbon dioxide).

B.
The reactants are C3H8 (propane) and O2 ( oxygen). The products are CO2 (carbon dioxide) and H2O (water).

C.
The reactants are CO2 (carbon dioxide) and H2O (water). The products are C3H8 (propane) and O2 ( oxygen).

D.
The reactants are O2 (oxygen) and CO2 (carbon dioxide). The products are C3H8 (propane) and H2O (water).

Sagot :

Answer:

B

Explanation:

Reactants are the compounds which reaction produce the products. In general terms this can be expressed symbolically as follows:

reactants -> products

Other phenomena like heat are omitted because are not always present, that is, only compounds are included. Therefore, in this reaction the reactants are C3H8 (propane) and O2 ( oxygen) and the products are CO2 (carbon dioxide) and H2O (water)

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Answer:

[tex]\huge \boxed{\mathrm{Option \ B}}[/tex]

[tex]\rule[225]{225}{2}[/tex]

Explanation:

[tex]\sf C_3 H_8 +O_2 \Rightarrow CO_2 + H_2 O[/tex]

Balancing Carbon atoms on the right side,

[tex]\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 + H_2 O[/tex]

Balancing Hydrogen atoms on the right side,

[tex]\sf C_3 H_8 +O_2 \Rightarrow 3CO_2 +4 H_2 O[/tex]

Balancing Oxygen atoms on the left side,

[tex]\sf C_3 H_8 +5O_2 \Rightarrow 3CO_2 +4 H_2 O[/tex]

The reactants are on the left side of the reaction:

[tex]\sf \boxed{\sf C_3 H_8 +O_2} \Rightarrow CO_2 + H_2 O[/tex]

Propane and oxygen are the reactants.

The products are on the right side of the reaction:

[tex]\sf C_3 H_8 +O_2 \Rightarrow \boxed{\sf CO_2 + H_2 O}[/tex]

Carbon dioxide and water are the products.

[tex]\rule[225]{225}{2}[/tex]

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