Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

find two numbers whose sum is 64 and whose difference is 42

Sagot :

These numbers are  "a"  and "b".  
Sum is 64,  so  a+b=64
Difference  is 42  so  a-b=42
So you've got:
[tex]+\begin{cases} a+b=64 \\ a-b=42\end{cases} \\ \overline{, \quad2a \quad \ = \ 106} \qquad /:2 \\ a=53[/tex]
When a+b=64 and a=53  you've got:
53+b=64
b=11

So these numbers is 53 and 11. 

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.