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Sagot :
j = number of cd's joel has
m = number of cd's mariella has
b = number of cd's blake has
from problem statement, develop equations:
j = 2m
b = (j - 7)/3 = 25
m = ?
solve for m
b = 25 = (j - 7)/3
25 = (j - 7)/3
25*3 = j - 7
75 + 7 = j
j = 82
j = 2m = 82
m = 82/2
m = 41
thus
mariella has 41 cd's
joel has 82 cd's
blake has 25 cd's
m = number of cd's mariella has
b = number of cd's blake has
from problem statement, develop equations:
j = 2m
b = (j - 7)/3 = 25
m = ?
solve for m
b = 25 = (j - 7)/3
25 = (j - 7)/3
25*3 = j - 7
75 + 7 = j
j = 82
j = 2m = 82
m = 82/2
m = 41
thus
mariella has 41 cd's
joel has 82 cd's
blake has 25 cd's
Answer:
We can write each of the statements as an equation
1. Joel j has twice the number of CDs as Mariella m, hence
j=2m
2. Joel's number of CD's - 7 divided by 3 equals the number of CDs Blake b has:
28j-729 2F3=b
3. Blake has 25 CDs
b=25
Substituting (3) into (2) gives:
%28j-7%29%2F3=25
j-7=3x25
j-7=75
j=75%2B7
j=82
So Joel has got 82 CD's
Based on equation (1) we can calculate the number of CD's Mariella has:
82=2m
m=82%2F2
m=41
Mariella has 41 CDs
Joel has 82 CDs
Blake has 25 CDs
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