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Sagot :
[tex]1\frac{2}{5}-\frac{3}{8}=\ \ \ | make\ improper\ fractions\\\\
\frac{7}{5}-\frac{3}{8}=\ \ \ | make\ a\ common\ denominator\\\\\frac{56}{40}-\frac{15}{40}=\frac{41}{40}\\\\Solution\ is\ \frac{41}{40}[/tex]
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