At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
[tex]\hbox{From formula} \ \ \ \sqrt{xy} = \sqrt{x} \cdot \sqrt{y} \ \hbox{you've got:} \\ \sqrt{-\frac{16}{169}}=\sqrt{-1 \cdot \frac{16}{169}}= \sqrt{-1} \cdot \sqrt{\frac{16}{169}} \\ \sqrt{-1} \ \hbox{is an imaginary unit so} \ \ \sqrt{-1} = i \\ \hbox{And from the formula:} \\ \sqrt{\frac{x}{y}}=\frac{\sqrt{x}}{\sqrt{y}} \ \hbox{you'll have:} \\ \frac{\sqrt{16}}{\sqrt{169}}i \\ \hbox{See that you can reach:} \\ \sqrt{16}=4 \qquad \hbox{because} \qquad 4^2=16 \\ [/tex]
[tex]\sqrt{16}=-4 \qquad \hbox{because} \qquad (-4)^2=16 \\ \hbox{The same to 169. Here, look that} \ \ 13^2=169 \\ \hbox{So you've got positive and negative possibility, so two roots.} \\ \hbox{First is principal root:} \\ \frac{4}{13}i \\ \hbox{And second root:} \\ -\frac{4}{13}i[/tex]
[tex]\sqrt{16}=-4 \qquad \hbox{because} \qquad (-4)^2=16 \\ \hbox{The same to 169. Here, look that} \ \ 13^2=169 \\ \hbox{So you've got positive and negative possibility, so two roots.} \\ \hbox{First is principal root:} \\ \frac{4}{13}i \\ \hbox{And second root:} \\ -\frac{4}{13}i[/tex]
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.
