Answered

Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

How do you solve (10-5r)^2 using fctoring

Sagot :

apologiabiology
(10-5r)^2=(10-5r)(10-5r) or 
25r^2-100r+100
divide the whole thing by 5 and get
5(5r^2-20r+20)
divide the whole thing by 5 again
25(r^2-4r+4)
factor by finding what two numbers add to get -4 and multiply to get 4 (-2 and -2 work)
r^2-4r+4=(r-2)(r-2) or 25((r-2)^2)
Look, that  10 - 5r = 5(2-r). So:
[tex](10-5r)^2 = \left[ 5(2-r)\right]^2 = 5^2 \cdot (2-r)^2 =25(2-r)^2\\ \hbox{These bracket we will delete using this formula:} \\ (a-b)^2 = a^2 - 2ab + b^2 \\ \hbox{So we've got:} \\ 25 \cdot (r^2 - 2 \cdot 2r + 2^2)=\boxed{25(r^2-4r+4)} \\ \hbox{Or if you want to have it without bracket:} \\ 25r^2-100r+100[/tex]
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.