Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

How do you solve (10-5r)^2 using fctoring

Sagot :

apologiabiology
(10-5r)^2=(10-5r)(10-5r) or 
25r^2-100r+100
divide the whole thing by 5 and get
5(5r^2-20r+20)
divide the whole thing by 5 again
25(r^2-4r+4)
factor by finding what two numbers add to get -4 and multiply to get 4 (-2 and -2 work)
r^2-4r+4=(r-2)(r-2) or 25((r-2)^2)
Look, that  10 - 5r = 5(2-r). So:
[tex](10-5r)^2 = \left[ 5(2-r)\right]^2 = 5^2 \cdot (2-r)^2 =25(2-r)^2\\ \hbox{These bracket we will delete using this formula:} \\ (a-b)^2 = a^2 - 2ab + b^2 \\ \hbox{So we've got:} \\ 25 \cdot (r^2 - 2 \cdot 2r + 2^2)=\boxed{25(r^2-4r+4)} \\ \hbox{Or if you want to have it without bracket:} \\ 25r^2-100r+100[/tex]
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.