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express the product in simplest form 8/2x+8 * x^2-16/4

Sagot :

From  formula a^2-b^2 = (a-b)(a+b) :
x^2 - 16 = (x-4)(x+4)

In 2x+8 factor out "2", you'll  reach  2(x+4).  So:

[tex]\frac{8}{2x+8} \cdot \frac{x^2-16}{4}=\frac{8(x-4)(x+4)}{2(x+4) \cdot 4}= \frac{8(x+4)(x-4)}{8(x+4)}= \boxed{x-4}[/tex]

(In finish  you delete 8(x+4) from nominator and denominator)
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