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Sagot :
[tex] \left \{ {{3x+2y=11\ \ \ \ \ \ \ } \atop {x-2y=4y\ \ | add\ 2y}} \right.\\\\ \left \{ {{3x+2y=11} \atop {x=4y+2y}} \right.\\\\substitution\ method\\\\
3(4y+2y)+2y=11\\\\
3*6y+2y=11\\\\
18y+2y=11\\\\
20y=11\ \ \ | divide\ by\ 20\\\\
y=\frac{11}{20}\\\\
x=6y=6* \frac{11}{20}=\frac{66}{20}=\frac{33}{10}\\\\
[/tex]
I know this is already answered but this is the answer simplified
(4, -1/2)
This is to help those that didn't understand the first guys explanation.
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