In [tex] \frac{50}{32} [/tex], you must find a common factor.
Since they are both even, 2 is a factor.
Divide both the numerator and denominator by 2
[tex] \frac{50}{32} [/tex]÷[tex] \frac{2}{2} [/tex]=[tex] \frac{25}{16} [/tex]
[tex] \frac{25}{16} [/tex] is the simplified improper fraction
But to find the mixed fraction, divide the numerator by the denominator
25÷16= [tex]1 \frac{56}{100} [/tex]
Put aside the whole number(1)
Since they are even numbers, 2 is a factor
[tex] \frac{56}{100} [/tex]÷[tex] \frac{2}{2} [/tex]=[tex] \frac{28}{50} [/tex]
Again, both the numerator and denominator are even numbers. So divide them by [tex] \frac{2}{2} [/tex] again
[tex] \frac{28}{50} [/tex]÷[tex] \frac{2}{2} [/tex]=[tex] \frac{14}{25} [/tex]
So get the whole number and add it to the answer
[tex]1+ \frac{14}{25} =1 \frac{14}{15} [/tex]
[tex]1 \frac{14}{25} [/tex] is your answer as a mixed fraction or [tex] \frac{25}{16} [/tex] as an improper fraction
