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Sagot :
[tex]5x+3y=-14\\
y=2\\\\
5x+3\cdot2=-14\\
5x+6=-14\\
5x=-20\\
x=-4[/tex]
yoyr going to just plug y right into the original equation and solve for x the way you would any normal problem with a single variable.
5x+3(2)=-14 | 5x+6=-14 | 5x=-20 | x=4 | if you need any extra help understanding this problem let me know and ill try to help out as much as i can
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