Answered

Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Solve, using the substitution method.

4x + 2y = 11
x – 2 = – 2y


A.


B.


C.


D.

Sagot :

naǫ
[tex]4x+2y=11 \\ x-2=-2y \\ \\ \hbox{from the 2nd equation:} \\ x-2=-2y \\ x=-2y+2 \\ \\ \hbox{substitute -2y+2 for x in the 1st equation:} \\ 4(-2y+2)+2y=11 \\ -8y+8+2y=11 \\ -8y+2y=11-8 \\ -6y=3 \\ y=-\frac{3}{6}=-\frac{1}{2} \\ \\ \hbox{solve one of the equations for x:} \\ x=-2 \cdot (-\frac{1}{2}) +2=1+2=3 \\ \\ \hbox{the answer:} \\ x=3 \\ y=-\frac{1}{2}[/tex]
TehGuyy
4x + 2y = 11
x - 2 = -2y
First you have to get a variable alone in one of the equations.

x - 2 = -2y
   +2    +2
--------------
x = -2y + 2
Next you substitute -2y +2 for x in the second equation.

4(-2y + 2) + 2y = 11
Distribute. 

-8y + 8 + 2y = 11
Combine like terms.

-6y + 8 = 11
Get the variable (y) by itself.

-6y + 8 = 11
       -8    -8
--------------------
-6y = 3
Finally get y by itself.

-6y = 3
-----   ------
-6      -6

Y = 0.5

Now to get x you plugin the answer for y.

x - 2 = -2y
x - 2 = -2(0.5)
x - 2 = -1
   +2     +2
x = 1

(1, 0.5) Is your ordered pair. :D

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.