At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Solve, using the substitution method.

4x + 2y = 11
x – 2 = – 2y


A.


B.


C.


D.



Sagot :

naǫ
[tex]4x+2y=11 \\ x-2=-2y \\ \\ \hbox{from the 2nd equation:} \\ x-2=-2y \\ x=-2y+2 \\ \\ \hbox{substitute -2y+2 for x in the 1st equation:} \\ 4(-2y+2)+2y=11 \\ -8y+8+2y=11 \\ -8y+2y=11-8 \\ -6y=3 \\ y=-\frac{3}{6}=-\frac{1}{2} \\ \\ \hbox{solve one of the equations for x:} \\ x=-2 \cdot (-\frac{1}{2}) +2=1+2=3 \\ \\ \hbox{the answer:} \\ x=3 \\ y=-\frac{1}{2}[/tex]
4x + 2y = 11
x - 2 = -2y
First you have to get a variable alone in one of the equations.

x - 2 = -2y
   +2    +2
--------------
x = -2y + 2
Next you substitute -2y +2 for x in the second equation.

4(-2y + 2) + 2y = 11
Distribute. 

-8y + 8 + 2y = 11
Combine like terms.

-6y + 8 = 11
Get the variable (y) by itself.

-6y + 8 = 11
       -8    -8
--------------------
-6y = 3
Finally get y by itself.

-6y = 3
-----   ------
-6      -6

Y = 0.5

Now to get x you plugin the answer for y.

x - 2 = -2y
x - 2 = -2(0.5)
x - 2 = -1
   +2     +2
x = 1

(1, 0.5) Is your ordered pair. :D