Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Solve, using the substitution method.

2x + 4y = 16
x – 7 = – 4y

Sagot :

konrad509
[tex]2x + 4y = 16\\ x - 7 = 4y\\\\ 2x + 4y = 16\\ x = 4y+7\\\\ 2(4y+7)+4y=16\\ 8y+14+4y=16\\ 12y=2\\ y=\frac{2}{12}=\frac{1}{6}\\\\ x=4\cdot\frac{1}{6}+7\\ x=\frac{4}{6}+7\\ x=\frac{2}{3}+\frac{21}{3}\\ x=\frac{23}{3}[/tex]
TehGuyy
Ugh why do you even have to use substitution method, the elimination method is so much easier in this instance... :/

Okay well first off you want to get x alone on one side of the equals sign.

x - 7 = -4y
  + 7    + 7
---------------
x = -4y + 7
Then you plugin -4y + 7 for x in the other equation.

2(-4y + 7) + 4y = 16
Then distribute.

-8y + 14 + 4y = 16
Combine like terms.

-4y + 14 = 16
       -14     -14
-----------------------
-4y = 2
----  ------
-4    -4

y = -0.5

x - 7 = -4(-0.5)
-----------------------
x - 7 = 2
   + 7  +7
----------------
x = 9

Then you plugin the answers for each variable to check, but I will let you do that.



Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.