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Particles q1, 92, and q3 are in a straight line.
Particles q1 = -1.60 x 10-19 C, 92 = +1.60 x 10-19 C,
and q3 = -1.60 x 10-19 C. Particles qi and q2 are
separated by 0.001 m. Particles q2 and q3 are
separated by 0.001 m. What is the net force on q2?


Sagot :

Answer: 0

Explanation: Acellus

The charge q2 is kept in between the  charges q1 and q3. The net force on charge q2 is zero.

What is force?

The force is the action of push or pull in order to move or stop the object.

Given, q1 = -1.60 x 10⁻¹⁹ C, q2 = +1.60 x 10⁻¹⁹ C, and q3 = -1.60 x 10⁻¹⁹ C. Particles q1 ,q2 and q2 , q3 are separated by d =0.001 m.

Net electrostatic force on q2 will be

F12 =F23

k q1 q2 / d² = kq2 q3 /d²

q1 q2 = q2 q3

Substitute the values of forces, we get

1.60 x 10⁻¹⁹ x 1.60 x 10⁻¹⁹  =  1.60 x 10⁻¹⁹ x 1.60 x 10⁻¹⁹  

1 =1

The net force F12 - F23 =0

Thus, the net force on q2 is zero.

Learn more about forces.

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