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Sagot :
Answer:
math = 24
English = 16
Philosophy = 8
Explanation:
Given that the college needs to make 8 less English courses available compared to math In each quarter
Let English = x , math = x + 8 ( in each quarter )
philosophy demand by student in each quarter = 1/2*x = x/2
limit of all three courses in a classroom = 48
i.e. x + (x+ 8 ) + x/2 = 48
= 2x + x/2 = 48 - 8
= 2x + x/2 = 40 ∴ 5x / 2 = 40
hence : x = 80 / 5 = 16
The number of sections of each course that the college should make available in each quarter to meet demand
math = x + 8 = 16 + 8 = 24
English = x = 16
Philosophy = x/2 = 16 / 2 = 8
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