Answer:
This reaction has infinite ways to be balanced
Explanation:
To balance this equation we can use the algebraic method:
N2O4(g) + CO → NO(g) + CO2(g)+NO2(g)
Where we write each molecule as a letter:
A + B → C + D + E
Then, we write the equations according the number of atoms of each molecule. That is:
Oxygen → 4A + B = C + 2D + 2E (1)
Nitrogen → 2A = C + E (2)
Carbon → B = D (3)
Then, we have to give 1 arbitral number for a letter. For example:
B = 1; D = 1
(1) 4A + 1 = C + 2 + 2E
4A = C + 2E + 1
2A = C + E (2) Twice (2):
4A = 2C + 2E
Subtracting (1) in (2)
C + 2E + 1 = 2C + 2E
C + 1 = 2C
1 = C
Si 1 = C:
4A + 1 = 1 + 2 + 2E
4A = 2 + 2E (1)
y:
2A = 1 + E (2)
Twice:
4A = 2 + 2E
As (1) and (2) are the same equation:
For example:
N2O4(g) + CO → NO(g) + CO2(g)+NO2(g)
