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what is the magnitude of -5+12i??

Sagot :

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Answer:

X has the form Ai + 16j, where A is some number greater than -12.

Then X + Y = (A+12)i, where A+12 > 0. So, X + Y lies along the positive x-axis.

Since we want the magnitude of X + Y to be the same as the magnitude of X, we have A+12 = √(A2+256)

Squaring both sides, we obtain A2 + 24A + 144 = A2 + 256

So, 24A + 144 = 256

24A = 112

A = 112/24 = 14/3

X = (14/3)i + 16j

The magnitude of X is √[(14/3)2 + 162] = 50/3

Step-by-step explanation:

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