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Help! This is due today and I'm stuck on this problem.
Brainiest for best answer.
NO LINKS! If you put a link, I will report you.
Find the area of the regular hexagon round answer to the nearest tenth.


Help This Is Due Today And Im Stuck On This Problem Brainiest For Best Answer NO LINKS If You Put A Link I Will Report You Find The Area Of The Regular Hexagon class=

Sagot :

Answer:

280.6 [tex]m^2[/tex]

Step-by-step explanation:

find the length of each side:

you're only given h = 9 m

the formula for h is  [tex]h=\frac{\sqrt{3} }{2} *a[/tex], where a is a side length of the hexagon

plug h in:

[tex]9=\frac{\sqrt{3}}{2}*a\\\\a=9*\frac{2}{\sqrt{3}}\\\\[/tex]

a ≈ 10.392 m

now find the area of a triangle:

1/2 (10.392)(9) = 46.764 [tex]m^2[/tex]

multiply that by 6 and you get 280.584 ≈ 280.6 [tex]m^2[/tex]

you can also use the regular hexagon area formula instead of finding the individual area and multiplying by 6: [tex]\frac{3\sqrt{3} }{2} *a^2[/tex]

280.6m2 is the correct answer