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Consider the oxidation of sodium metal to sodium oxide described by the balanced equation:
4 Na + O2 → 2 Na2O. What is the theoretical yield of Na2O in grams from 9.0 mol of O2?

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Sagot :

MenacingToast

Answer:

1116g

Explanation:

We'll convert moles O2 -> moles of Na2O -> grams of Na2O.

Based on our balanced equation, we have 1 mole of O2 for every 2 moles of Na2O. This is our mole to mole ratio.

9 mol O2 x [tex]\frac{2 mol Na2O}{1 mol O2}[/tex] = 18 mol Na2O

We can convert mols -> grams using the molar mass of Na2O- 62g.

18 mol Na2O x [tex]\frac{62g Na2O}{1 mol}[/tex] = 1116g

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