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Sagot :

Answer:

The heat contained is 1236 Joules

Explanation:

As we know

[tex]Q = mc\Delta[/tex]T

Where

[tex]\Delta[/tex]T is the change in temperature

m is the mass in grams

c is the specific heat of water (ice) = 2.06 joules/gram

Substituting the given values, we get -

[tex]Q = 20 * (-15+45)*2.06\\Q = 20*2.06*30\\Q = 1236[/tex]Joules

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