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Given:

The figure of circle E. [tex]m\angle ABD=(11x-3)^\circ,m\angle ACD=(8x+15)^\circ[/tex].

To find:

The measure of arc AD.

Solution:

We know that the inscribed angles on the same arc are congruent and their measures are equal.

[tex]\angle ABD[/tex] and [tex]\angle ACD[/tex] are inscribed angles on the same arc AD. So,

[tex]m\angle ABD=m\angle ACD[/tex]

[tex]11x-3=8x+15[/tex]

[tex]11x-8x=3+15[/tex]

[tex]3x=18[/tex]

[tex]x=6[/tex]

Now,

[tex]m\angle ABD=(11x-3)^\circ[/tex]

[tex]m\angle ABD=(11(6)-3)^\circ[/tex]

[tex]m\angle ABD=(66-3)^\circ[/tex]

[tex]m\angle ABD=63^\circ[/tex]

We know that the intercepted arc is always twice of the inscribed angle.

[tex]m(Arc(AD))=2\times m\angle ABD[/tex]

[tex]m(Arc(AD))=2\times 63^\circ[/tex]

[tex]m(Arc(AD))=126^\circ[/tex]

Therefore, the measure of arc AD is 126 degrees.

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