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Sagot :
Answer:
the force of attraction between the two charges is 4.2 x 10⁹ N.
Explanation:
Given;
the magnitude of first charge, q₁ = 0.06 C
the magnitude of the second charge, q₂ = 0.07 C
distance between the two charges, r = 3 m
The force of attraction between the two charges is calculated as ;
[tex]F = \frac{Kq_1q_2}{r^2}[/tex]
where;
k is Coulomb's constant = 9 x 10⁹ Nm²/C²
[tex]F = \frac{Kq_1q_2}{r^2} \\\\F = \frac{(9\times 10^9)(0.06)(0.07)}{3^2} \\\\F = 4.2 \times 10^{6} \ N[/tex]
Therefore, the force of attraction between the two charges is 4.2 x 10⁹ N.
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