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A 45.0 cm3 sample of gas is heated from 280. K to 315 K. What is the new volume of the gas sample?

Sagot :

samueladesida43

Answer:

50.63 cm³

Explanation:

Using Charles law equation as follows:

V1/T1 = V2/T2

Where;

V1 = initial volume (cm³)

V2 = final volume (cm³)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the question, V1 = 45.0 cm³, V2 = ?, T1 = 280 K, T2 = 315 K

Using; V1/T1 = V2/T2

45/280 = V2/315

Cross multiply

45 × 315 = 280 × V2

14175 = 280V2

V2 = 14175 ÷ 280

V2 = 50.625

V2 = 50.63 cm³

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