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Sagot :
Answer:
Option B is correct
Step-by-step explanation:
because when you compare the table with graph you can understand easily.
Option B would be correct because if there is one cat that has the frequency of two dots, two cats have the frequency of 3 dots, three cats have the frequency of 1 dot, and 4 cats have the frequency of 4 dots, then it would be correct.
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