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How would you write the equation with a slope of 2/3 and a y-intercept of -3 in slope- intercept form

Sagot :

Rohitknight

y=2/3x-2

Explanation:

The equation of a line can be written as y=mx+c

m=slope and c = y-intercept

The point at the x−intercept has coordinates (-3,0)

In y=mx+c

0=2/3(3)+c

0=2+c

-2=c

The equation is y=2/3x-2

Hrishii

Answer:

[tex] y = \frac{2}{3} x - 3[/tex]

Step-by-step explanation:

Slope (m) = 2/3

y-intercept (b) = - 3

Equation of line in slope intercept form is given as:

[tex] y = mx + b[/tex]

Plug the values of m and b in the above equation, we find:

[tex]y = \frac{2}{3} x + ( - 3) \\ \\ y = \frac{2}{3} x - 3[/tex]

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