Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

A rectangular parking lot has a length that is yards greater than the width. The area of the parking lot is square yards. Find the length and the width.

Sagot :

Answer:

length =  18yd

Width = 10yd

Step-by-step explanation:

Complete question

A rectangular parking lot has a length that is 8 yards greater than the width. The area of the parking lot is 180 square yards. Find the length and the width.

Area of the parking lot - length * width

A = LW

Given

Area = 180sq. yd

If the parking lot has a length that is 8 yards greater than the width, then;

L = 8 + W

The area becomes;

A = (8+W)W

180 = 8W+W²

W²+8W - 180 = 0

W²+18W-10W - 180 = 0

W(W+18)-10(W+18) = 0

(W-10)(W+18) = 0

W-10 = 0

W = 10yd

Since L = 8 + W

L = 8 + 10

L = 18yd

Hence the length and the width area 18yd and 10yd respectively