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Sagot :
Answer:
The volume is 40.96 cubic feet
Step-by-step explanation:
Given
[tex]V\ \alpha\ h * d^2[/tex]
Where
[tex]V = Volume\\ h = height\\ d = distance[/tex]
[tex]V = 15.84ft^3; h =22ft; d = 3ft[/tex]
Required
The volume when h = 32 and d = 4
[tex]V\ \alpha\ h * d^2[/tex]
Express as an equation
[tex]V = khd^2[/tex]
Where k is the constant of variation.
Make k the subject
[tex]k = \frac{V}{hd^2}[/tex]
Substitute [tex]V = 15.84ft^3; h =22ft; d = 3ft[/tex]
[tex]k = \frac{15.84}{22 * 3^2}[/tex]
[tex]k = \frac{15.84}{22 * 9}[/tex]
[tex]k = \frac{15.84}{198}[/tex]
[tex]k = 0.08[/tex]
To solve for V when h = 32 and d = 4, we have:
[tex]V = khd^2[/tex]
[tex]V = 0.08 * 32 * 4^2[/tex]
[tex]V = 0.08 * 32 * 16[/tex]
[tex]V = 40.96[/tex]
The volume is 40.96 cubic feet
The volume of the wood obtained from a tree that is 32 feet tall having a measurement of 4 feet around the trunk is [tex]40.96 \: \rm ft^3[/tex]
What is directly proportional and inversely proportional relationship?
Let there are two variables p and q
Then, p and q are said to be directly proportional to each other if
[tex]p = kq[/tex]
where k is some constant number called constant of proportionality.
This directly proportional relationship between p and q is written as
[tex]p \propto q[/tex] Â where that middle sign is the sign of proportionality.
In a directly proportional relationship, increasing one variable will increase another.
Now let m and n are two variables.
Then m and n are said to be inversely proportional to each other if
[tex]m = \dfrac{c}{n} \\\\ \text{or} \\\\ n = \dfrac{c}{m}[/tex]
(both are equal)
where c is a constant number called constant of proportionality.
This inversely proportional relationship is denoted by
[tex]m \propto \dfrac{1}{n} \\\\ \text{or} \\\\n \propto \dfrac{1}{m}[/tex]
As visible, increasing one variable will decrease the other variable if both are inversely proportional.
For this case, we have:
V = volume of the wood varying jointly as height of the tree and square of the distance around the trunk.
Let we take:
- r = distance of the wood around the trunk (in feet)
- h = height of the tree ( in feet)
V will of course increase as r or h increases, and as it varies jointly, thus:
[tex]V \propto h r^2[/tex]
Let  the constant of proportionality be 'k', then:
[tex]V = kr^2h[/tex] (in cubic foot)
For case 1, it was specified that V = 15.84 cubic foot when r = 3 ft and h = 22 ft,
Putting these values gives us:
[tex]15.84 = k(3)^2(22)\\\\k = \dfrac{15.84}{198} = 0.08[/tex]
Thus, we have:
[tex]\rm V = 0.08r^2 h \: \rm ft^3[/tex]
Assuming second wood was also obtained from same kind of tree, we get the volume of the wood for h = 32 and r = 4 feet as:
[tex]V = 0.08 (4)^2 (32) = 40.96 \: \rm ft^3[/tex]
Thus, the volume of the wood obtained from a tree that is 32 feet tall having a measurement of 4 feet around the trunk is [tex]40.96 \: \rm ft^3[/tex]
Learn more about proportionality here:
https://brainly.com/question/13082482
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