Answer:
The length of the vector is of [tex]\sqrt{194}[/tex]
The unit vector with the direction of PQ is [tex](\frac{8}{\sqrt{194}}, \frac{9}{\sqrt{194}}, \frac{7}{\sqrt{194}}[/tex]
Step-by-step explanation:
Vector from point P(3,-5,2) to Q(-5,4,9)
The vector is:
[tex]PQ = Q - P = (-5-3, 4-(-5), 9-2) = (8,9,7)[/tex]
The length is:
[tex]\sqrt{8^2+9^2+7^2} = \sqrt{194}[/tex]
The length of the vector is of [tex]\sqrt{194}[/tex]
Find a unit vector with the direction of PQ
We divide each component of vector PQ by its length. So
[tex](\frac{8}{\sqrt{194}}, \frac{9}{\sqrt{194}}, \frac{7}{\sqrt{194}}[/tex]
The unit vector with the direction of PQ is [tex](\frac{8}{\sqrt{194}}, \frac{9}{\sqrt{194}}, \frac{7}{\sqrt{194}}[/tex]
