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Sagot :
Answer:
The focus of the ellipse are;
(-12·√(10), -8) and (12·√(10), -8)
Step-by-step explanation:
The given equation for the ellipse is presented as follows;
[tex]\dfrac{x^2}{46} + \dfrac{(y + 8)^2}{26} = 1[/tex]
From the general equation of the ellipse, we have;
[tex]\dfrac{(x - h)^2}{a^2} + \dfrac{(y - k)^2}{b^2} = 1[/tex]
The focus of the ellipse are, (h - c₁, k) and (h + c₁, k)
By comparison, we get;
h = 0, k = -8, a = 46, b = 26
We have;
c² = a² - b²
c² = 46² - 26² = 1440
c = 12·√(10)
The focus of the ellipse are therefore;
(0 - 12·√(10), -8) = (-12·√(10), -8), and (0 + 12·√(10), -8) = (12·√(10), -8).
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