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\dfrac{x^2}{46}+\dfrac{(y+8)^2}{26}=1 46 x 2 ​ + 26 (y+8) 2 ​ =1start fraction, x, squared, divided by, 46, end fraction, plus, start fraction, left parenthesis, y, plus, 8, right parenthesis, squared, divided by, 26, end fraction, equals, 1 What are the foci of this ellipse? Choose 1 answer:

Sagot :

Answer:

The focus of the ellipse are;

(-12·√(10), -8) and (12·√(10), -8)

Step-by-step explanation:

The given equation for the ellipse is presented as follows;

[tex]\dfrac{x^2}{46} + \dfrac{(y + 8)^2}{26} = 1[/tex]

From the general equation of the ellipse, we have;

[tex]\dfrac{(x - h)^2}{a^2} + \dfrac{(y - k)^2}{b^2} = 1[/tex]

The focus of the ellipse are, (h - c₁, k) and (h + c₁, k)

By comparison, we get;

h = 0, k = -8, a = 46, b = 26

We have;

c² = a² - b²

c² = 46² - 26² = 1440

c = 12·√(10)

The focus of the ellipse are therefore;

(0 - 12·√(10), -8) = (-12·√(10), -8), and (0 + 12·√(10), -8) = (12·√(10), -8).

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