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In the first half of the basketball season, Jean made 15 free throws out of the 25 free throws she attempted, for a free-throw shooting percentage of 60%. How many consecutive free-throw shots would Jean have to make to raise her free-throw shooting percentage to 80%?

Sagot :

Answer:

She has to make 25 consecutive free throws

Step-by-step explanation:

Let the number of consecutive throws be x

So, that would mean the number of free throws would total 25 + x

while the number of free throws made would be 15 + x

So for us to have an 80% raise ;

That would mean;

(15 + x)/(25 + x) * 100 = 80

100(15 + x) = 80(25 + x)

1500 + 100x = 2000 + 80x

2000-1500 = 100x-80x

20x = 500

x = 500/20

x = 25

shamusmcgraw

Answer:

She has to make 25 consecutive free throws

Step-by-step explanation:

Let the number of consecutive throws be x

So, that would mean the number of free throws would total 25 + x

while the number of free throws made would be 15 + x

So for us to have an 80% raise ;

That would mean;

(15 + x)/(25 + x) * 100 = 80

100(15 + x) = 80(25 + x)

1500 + 100x = 2000 + 80x

2000-1500 = 100x-80x

20x = 500

x = 500/20

x = 25

Step-by-step explanation:

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