At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

A dodecahedral die (one with 12 sides numbered from 1 to 12) is tossed once. Find the following probability. (Enter your probability as a fraction.)
The number on the upward face is not 4.

Sagot :

Answer:

11/12

Step-by-step explanation:

::::::::::::::::

The probability of the number on the upward face is not 4 would be 11/12 or 0.92 by calculating as follows:

Solution:

The possible outcomes for rolling a dodecahedral die, numbered from 1 to 12, once is given below in the term of sample space S:

S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12}.

Therefore,

n(S) = 12

Event A: Sample space in the case of not having number 4 on the upward face:

A = {1, 2, 3, 5, 6, 7, 8, 9, 10, 11, 12}

therefore,

n(A) = 11

  • the probability of an event can be calculated by:

the required probability = [tex]\dfrac{\text{Number of times event A, occurred}}{\text{Number of times this experiment performed}}[/tex]

then putting the space values here;

 = [tex]\frac{n(A)}{n(S)}=\frac{11}{12}=0.92[/tex]

Thus, the required probability is 0.92

Learn more about the probability of an event:

https://brainly.com/question/24028840

View image Histrionicus