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Sagot :
Answer:
Explanation:
Energy stored in a solenoid per unit volume = B₀² / (2μ₀)
B₀= μ₀ n I₀
n is no of turns per unit length .
Energy stored in a solenoid per unit volume = ( μ₀ n I₀)² / (2μ₀)
=μ₀n²I₀²/2
n = 40 turns / cm = 40 x 100 turns per meter.
I₀ = 5000A .
Putting the values
Energy stored in a solenoid per unit volume
= 4π x 10⁻⁷ x 40 x 10² x 5000² /2
= 1256 J/ m³
Volume of solenoid = cross sectional area x length
= 28 x 10⁻⁴ x .10 = 2.8 x 10⁻⁴ m³
Total energy stored = 1256 J / m³ x 2.8 x 10⁻⁴ m³
= .35 J .
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