Answered

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An 18 kg weight is lifted up to 12 m in height and then released in free fall. What are the potential energy, kinetic energy and total energy at: The highest point? 3 m above the ground? At the ground?

Sagot :

akiran007

Answer:

1) at the highest Point

KE= 0  PE=2116.8 N

2) 3 m above the ground

PE= 529.2 N KE=1587.6 N

3) at the ground

KE= 2116.8 N and PE=0

Step-by-step explanation:

The potential energy is given by

PE= mgh   where m is the mass , g is the acceleration due to gravity which is equal to 9.8 m/s² and h is the height.

The kinetic energy is given by KE= 1/2 mv² where m is the mass of the body and v is the velocity.

1) at the highest Point

Now at the highest point the  velocity is zero

KE= 1/2 mv²

KE= 0

PE = mgh

PE= 18 *9.8* 12= 2116.8 N

Total Energy = KE + PE= 0 + 2116.8 N= 2116.8 N

2) 3 m above the ground

At 3 m above the ground

PE= mgh

PE= 18 *9.8* 3= 529.2 N

According to law of conservation of energy the total energy ( sum of KE and PE)  remains the same at every point.

Total Energy = KE + PE

2116.8 N-529.2N= 1587.6N

KE=1587.6 N

3) at the ground

at the ground the height will be zero

PE= mgh

PE= 18 *9.8* 0= 0 N

According to law of conservation of energy the total energy ( sum of KE and PE)  remains the same at every point.

Total Energy = KE + PE

2116.8 N=2116.8 N + 0

KE= 2116.8 N

or

KE= 1/2 mv²

KE = 1/2* 18 *(15.36)²= 2116.8

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